The electronic configurations of some atoms are given below, which of these should have the highest — Periodic Table and Periodicity Chemistry Question

💡 Solution & Explanation

Second ionization energy is the energy required to remove the second electron after the removal of first electron from its outermost orbital. The order of stability of electronic configuration is- Fully filled>Half-filled Therefore, the electronic configuration is given as- 2 2 6 1 1 ,2 ,2 ,3 s s p s In this, the removal of the first electron from its outermost orbital requires less energy than the removal of the second electron. Thus, the correct option is (b) 2 2 6 1 1 ,2 ,2 ,3 s s p s .