2 + 3 Ca(OH)2()2 + 6 Equivalent weight of in this reaction is — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

Equivalent weight Molecular weight Valency factor Valency factor for acid= no. of H-atoms replaced per molecule ∴From reaction, 3 4 2 3 4 2 2 2 3 ( ) ( ) 6 H PO Ca OH Ca PO H O -> It is clear that 3 4 H PO loses 3 H-atoms per molecule ∴ Eq.wt. 98 32.66 3 142. The Ew of H3PO4 in the reaction is Ca(OH)2 + H3PO4CaHPO4 + 2H2O (Ca = 40, P = 31, O = 16) (a) 49 (b) 98 (c) 32.66 (d) 147 ∴From the reaction, 2 3 4 4 2 ( ) 2 Ca OH H PO CaHPO H O -> It is clear that, 3 4 H PO loses only 2 H-atoms ∴ It’s valency factor=2 ∴Eq.wt. of 3 4 98 49 2 H PO 143. 0.1 g of metal combines with