10 mL of 0.2 N HCl and 30 mL of 0.1 N HCl together exactly neutralises 40 mL of solution of NaOH, which is also exactly neutralised by a solution in water of 0.61 g of an organic acid.What is the equi

Question

10 mL of 0.2 N HCl and 30 mL of 0.1 N HCl together exactly neutralises 40 mL of solution of NaOH, which is also exactly neutralised by a solution in water of 0.61 g of an organic acid.What is the equivalent weight of the organic acid ?

Prashant Kotian · Accepted Answer

Correct answer: B. Number of millimoles of 1 100 100 NaOH x ∴ Number of milliequivalent of NaOH =millimoles × valency factor =100 1 100 x ∴Number of milliequivalent of 2 4 10 10 100 H SO x Number of milliequivalent of NaOH=Number of milliequivalent of 2 4 H SO The resultant solution will be neutral.

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