10 mL of 0.2 N HCl and 30 mL of 0.1 N HCl together exactly neutralises 40 mL of solution of NaOH, wh — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

Number of millimoles of 1 100 100 NaOH x ∴ Number of milliequivalent of NaOH =millimoles × valency factor =100 1 100 x ∴Number of milliequivalent of 2 4 10 10 100 H SO x Number of milliequivalent of NaOH=Number of milliequivalent of 2 4 H SO The resultant solution will be neutral.