Mixture X = 0.02 mole of [Co ()5 ] Br and 0.02 mole of [Co()5 Br] was prepared in 2L of solution. 1 L of mixture X + excess - Y 1 L of mixture X + excess - Z Number of moles of Y and Z are

Question

Mixture X = 0.02 mole of [Co ($NH_3$)5 $SO_4$] Br and 0.02 mole of [Co($NH_3$)5 Br] $SO_4$ was prepared in 2L of solution. 1 L of mixture X + excess $AgNO_3$-> Y 1 L of mixture X + excess $BaCl_2$-> Z Number of moles of Y and Z are

Prashant Kotian · Accepted Answer

Correct answer: A. Liters of the given mixture X contains 0.01 moles of each of the given complexes Also with 3 AgNO , only 3 5 4 [Co(NH ) SO ]Br reacts to give silver bromide as ppt. the reaction involved is 3 5 4 3 3 5 4 3 [Co(NH ) SO ]Br+AgNO [Co(NH ) SO ]NO +AgBr -> Similarly for the second reaction 4 BaSO will be precipitated. Hence, the correct answer is option (a)

💡 Solution & Explanation

Practice 22,000+ questions like this