The molar freezing point constant for water is 1.86º C/m. If 342g of cane sugar () is dissolved in 1 — Solutions and Colligative Properties Chemistry Question
Question
The molar freezing point constant for water is 1.86º C/m. If 342g of cane sugar ($C_12H_22O_11$) is dissolved in 1000 g of water, the solution will freeze at
Answer: A
💡 Solution & Explanation
342 g of cane sugar (sucrose) is equivalent to 342 342 mole 342 g of sugar = 1 mole molality = 1m 0 0 0 0 1.86 (since m = 1 ) we know that , 1.86 (since = 0 ) f f f f f f f f f T K m T K C T T T T C T x >>
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