In decimolar solution, is ionised to the extent of 1.3%. If log 1.3 = 0.11, what is the pH of the so — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

From the given conditions, we know that- 3 3 3 3 CH COOH CH COO H 0.1 0 0 0. 1(1- ) 0.1 0.1 K [H ][CH COO ]/[CH COOH] a 2 1.3 α 100 [H ] 0.1 1.3 10 pH log[H ] pH 3 log1.3 3 0.11 2.89 x x