A certain buffer solution contains equal concentration of X– and HX. the Ka for HX is 10–8. The pH o — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

We know that, loss of proton from HX belongs to an acidic buffer. So, to calculate its pH we have- a a 8 pH = pK +log [conjugate base]/[acid] pH pK log[X ]/[HX] pH log[10 ]+log1 (i.e. [X ]=[HX]) pH =8