Ka for HF is 3.5 × 10–4. Calculate Kb for the fluoride ion. — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

HF and F are conjugate Acid-Base pair (CABP) for CABP, a b w K K = K x 14 11 w b 4 a K 10 K 2.86 10 K 3.5 10 x x IONIC EQUILIBRIUM 43 Salt Hydrolysis