Aq. solution of sodium cyanide is — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

I don't see the answer options (A, B, C, D) in your question. To provide a proper step-by-step solution explaining why C is correct, please share the complete question with all options. However, I can outline the **general chemistry** of aqueous sodium cyanide: **Key Points about $NaCN$ solution:** 1. **Ionization:** $NaCN \rightarrow Na^+ + CN^-$ (complete in water) 2. **Hydrolysis of $CN^-$:** $$CN^- + H_2O \rightleftharpoons HCN + OH^-$$ The cyanide ion is a weak conjugate base of weak acid $HCN$ ($K_a = 4.9 \times 10^{-10}$) 3. **Solution is basic** due to hydrolysis of $CN^-$, producing $OH^-$ ions 4. **Poisonous nature:** $HCN$ is extremely toxic; any acidification releases toxic $HCN$ gas **If option C states:** "basic/alkaline" or "poisonous" or "undergoes hydrolysis" — these would be correct. Please provide the options so I can confirm which specific property option C refers to and why others are wrong.