The correct representation for solubility product of is — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

# Solubility Product of $SnS_2$ **Step 1: Write the dissolution equation** $SnS_2(s) \rightleftharpoons Sn^{4+}(aq) + 2S^{2-}(aq)$ **Step 2: Identify the stoichiometry** From the balanced equation: - 1 mole of $SnS_2$ produces 1 mole of $Sn^{4+}$ and 2 moles of $S^{2-}$ **Step 3: Apply the solubility product expression** The solubility product constant includes only the ions in solution, raised to the power of their stoichiometric coefficients: $$K_{sp} = [Sn^{4+}][S^{2-}]^2$$ **Key points:** - The solid $SnS_2$ is not included in the expression (its activity = 1) - The concentration of $S^{2-}$ is squared because the stoichiometric coefficient is 2 - $Sn^{4+}$ appears with power 1 Therefore, **option A** correctly represents: $$K_{sp} = [Sn^{4+}][S^{2-}]^2$$