A monoprotic acid in 1.00 M solution is 0.01% ionised. The dissociation constant of this acid is — Ionic Equilibrium Chemistry Question
Question
A monoprotic acid in 1.00 M solution is 0.01% ionised. The dissociation constant of this acid is
Answer: A
💡 Solution & Explanation
Monoprotic acid dissociates as HA H A α 0.01% 4 α 0.0001 10 K α C a 2 2 4 K = α C = 10 1 x a 8 K = 10 a
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