A sample of calcium carbonate () has the following percentage composition: Ca = 40%, C = 12%, O = 48%. If the law of constant proportions is true, then the weight of calcium in 4g of a sample of calci

Question

A sample of calcium carbonate ($CaCO_3$) has the following percentage composition: Ca = 40%, C = 12%, O = 48%. If the law of constant proportions is true, then the weight of calcium in 4g of a sample of calcium carbonate obtained from another source will be:

Prashant Kotian · Accepted Answer

Correct answer: C. In 100g CaCO3, 40g Ca is present. In 4g CaCO3, Let x g Ca be present x 40 4 100 >> x = 1.6g

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