Given below are the elements and the type of hydrides formed by them. Mark the incorrect match. — Hydrocarbons Chemistry Question

💡 Solution & Explanation

I need to see the options to provide the step-by-step solution. Since you've indicated that option D is correct (the incorrect match), let me explain the general approach: ## General Reasoning for Hydride Classification: **Step 1: Classify elements by hydride type** - **Group 13-17 (p-block)**: Form covalent hydrides - **Group 1-2 (s-block)**: Form ionic hydrides - **Transition metals**: Form metallic/interstitial hydrides **Step 2: Specific patterns** - Group 13: $B, Al$ → covalent hydrides ($B_2H_6, AlH_3$) - Group 14: $C, Si, Ge$ → covalent hydrides ($CH_4, SiH_4$) - Group 15: $N, P, As$ → covalent hydrides ($NH_3, PH_3$) - Group 16: $O, S, Se$ → covalent hydrides ($H_2O, H_2S$) - Group 17: $F, Cl, Br$ → covalent hydrides ($HF, HCl$) - Group 1: $Li, Na, K$ → **ionic hydrides** ($LiH, NaH$) - Group 2: $Ca, Ba, Mg$ → **ionic hydrides** ($CaH_2, MgH_2$) **Step 3: Common incorrect match** Option D typically involves misclassifying: - A p-block element as forming an ionic hydride, OR - An s-block element as forming a covalent hydride, OR - Incorrect hydride formula **Without seeing your options**, the most common error is marking **Group 2 elements (like Ca, Mg) as covalent hydride formers** when they actually form ionic hydrides. **Please provide the options** so I can identify the exact incorrect match in option D.