The compound which does not show paramagnetism is — Coordination Compounds Chemistry Question

💡 Solution & Explanation

I need to identify which compound is diamagnetic (does not show paramagnetism). However, the answer options aren't provided in your question. Let me explain the general approach: **Key Principle:** - **Paramagnetic compounds** have unpaired electrons (attracted to magnetic field) - **Diamagnetic compounds** have all paired electrons (repelled by magnetic field) **General Strategy to Determine Paramagnetism:** 1. Write the electron configuration 2. Count unpaired electrons: - If unpaired electrons exist → paramagnetic - If all electrons are paired → diamagnetic **Common Examples:** | Compound | Configuration | Unpaired e⁻ | Nature | |----------|---------------|-------------|---------| | $O_2$ | $(\sigma_{2p})^2(\pi_{2p})^4(\pi^*_{2p})^2$ | 2 | Paramagnetic | | $N_2$ | $(\sigma_{2p})^2(\pi_{2p})^4$ | 0 | Diamagnetic | | $Cu^{2+}$ | $[Ar]3d^9$ | 1 | Paramagnetic | | $Zn^{2+}$ | $[Ar]3d^{10}$ | 0 | Diamagnetic | **Answer B is likely correct if it represents:** - A transition metal with d¹⁰ configuration (like $Zn^{2+}$, $Cu^+$) - A noble gas or fully filled shell configuration - A molecule with all paired electrons (like $N_2$, $CO_2$) **Please provide the options** so I can give a specific explanation for why B is diamagnetic.