When 2-chloro-2-methylbutane is heated with alcoholic KOH, the possible product/s is/are (i) ()2 C= (ii) =C() (iii) ()2CHCH=

Question

When 2-chloro-2-methylbutane is heated with alcoholic KOH, the possible product/s is/are (i) ($CH_3$)2 C=$CHCH_3$ (ii) $CH_2$=C($CH_3$)$CH_2CH_3$ (iii) ($CH_3$)2CHCH=$CH_2$

Prashant Kotian · Accepted Answer

Correct answer: D. The possible products obtained when 2-chloro-2-methylbutane with alcoholic KOH are 2-methyl but-2-ene and 2-methyl but-1-ene. Alcoholic KOH is a strong base and the chloro group is a good leaving group as shown- 3 2 3 3 ( )( ) KOH CH CH C CH Cl CH -> 2 3 2 3 3 3 3 ( ( ) ) CH C CH CH CH CH CH C CH CH

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