The correct representation for solubility product of is — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

# Solubility Product of $SnS_2$ **Step 1: Write the dissolution equation** $SnS_2(s) \rightleftharpoons Sn^{4+}(aq) + 2S^{2-}(aq)$ **Step 2: Apply the solubility product expression** The solubility product constant $K_{sp}$ includes only aqueous ions (not the solid): $$K_{sp} = [Sn^{4+}][S^{2-}]^2$$ **Step 3: Explain the exponents** - $Sn^{4+}$ appears with coefficient 1 in the dissolution equation → exponent is 1 - $S^{2-}$ appears with coefficient 2 in the dissolution equation → exponent is 2 **Key point:** The exponents in the $K_{sp}$ expression correspond directly to the stoichiometric coefficients from the balanced dissolution equation. Therefore, **Option A is correct**: $K_{sp} = [Sn^{4+}][S^{2-}]^2$