Ionic EquilibriummediumMCQ SINGLE

The dissociation constant of HCN is 5 × 10 –10. The pH of the solution prepared by mixing 1.5 mole oIonic Equilibrium Chemistry Question

Question

The dissociation constant of HCN is 5 × 10 –10. The pH of the solution prepared by mixing 1.5 mole of HCN and 0.15 moles of KCN in water and making up the total volume to 0.5 dm 3 is

Answer: C

💡 Solution & Explanation

The solution of HCN and KCN in water is an acidic buffer. No. of moles 1.5 HCN 3M Total volume 0.5 0.15 KCN 0.3M 0.5 a 10 salt pH = pK + log acid IONIC EQUILIBRIUM 42 10 10 0.3 pH = log 5 10 log 3 x pH = 9.3 1 pH = 9.3 1= 8.3

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