In the redox reaction, xKMnO NH yKNO MnO KOH H O -> x and y are — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

The given reaction is- 4 3 3 2 2 xKMnO +NH yKNO +MnO +5KOH+H O -> First, we need to find out the oxidation state of central atom i.e. Mn and N +7 -3 +5 +4 4 3 3 2 2 xKMnO +N H yKNO +MnO +5KOH+H O -> We can calculate the change in oxidation state.Change in oxidation state of Mn is 3 Change in oxidation state of N is 8 We will cross multiply the change as shown in the figure 4 3 2 3 2 K Mn O + N H MnO +KNO +KOH+H O +7 -3 +4 +5 -> Hence, the balanced equation can be written as- 4 3 3 2 2 8KMnO +3NH 3KNO +8MnO +5KOH+2H O -> Thus, the correct option is (d) x=8, y=3