For a reversible reaction : A + B C dx dt = 2.0 × 103 L mol–1 s–1 [A] [B] – 1.0 × 102 s–1 [C] where x is the amount of ‘A’ dissociated. The value of equilibrium constant (Keq) is :

Question

Prashant Kotian · Accepted Answer

Correct answer: C. at eq. Rate of conc. is zero. Thus at eq., 3 1 1 2 1 2 1 3 1 1 3 c 2 0 2 10 L mol s A B 1.0 10 s C 1.0 10 s C 2 10 L mol s A B C 2 10 20 K A B 1.0 10 x x >> x x x x

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