The rate constant for forward and backward reactions of hydrolysis of ester are 1.1 × 10–2 and 1.5 × 10–3 per minute respectively. Equilibrium constant for the reaction is + +

Question

The rate constant for forward and backward reactions of hydrolysis of ester are 1.1 × 10–2 and 1.5 × 10–3 per minute respectively. Equilibrium constant for the reaction is $CH_3COOC_2H_5$ + $H_2O$ $CH_3COOH$ + $C_2H_5OH$

Prashant Kotian · Accepted Answer

Correct answer: D. 3 2 5 3 2 5 2 CH COOH C H OH k = ... i CH COOC H H O According to rate law rate of forward reaction f f 3 2 5 2 R =K CH COOC H H O And rate of backward reaction b b 3 2 5 R =K CH COOH C H OH f b n Eq R = R 3 2 5 f b 3 2 5 2 CH COOH C H OH K = = K K CH COOC H H O 2 -3 1.1×10 K= 7.33 1.5×10 equilibrium constant will remain unaltered.

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