Calculate the number of oxygen atoms required to combine with 7.0g of to form if 80% of is converted into products. N O N O -

Question

Calculate the number of oxygen atoms required to combine with 7.0g of $N_2$ to form $N_2O_3$ if 80% of $N_2$ is converted into products. N O N O ->

Prashant Kotian · Accepted Answer

Correct answer: B. 2 2 2 3 3 2 N O N O -> 1 mol of 2 N combine with 1.5 mole of 2 O 2 2 7 80 moles of N needs 0.3 mol of O 28 100 x 23 23 2 2 0.3 moles of O 6.022 10 0.3 1.8 10 molecules of O x x x . Therefore, No. of O-atoms =2×0.3× 23 23 6 10

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