How many moles of ferric alum (NH ) SO Fe (SO ) .24 can be made from the sample of Fe containing 0.0056 g of it ?

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Question

How many moles of ferric alum (NH ) SO Fe (SO ) .24 $H_2O$ can be made from the sample of Fe containing 0.0056 g of it ?

Prashant Kotian · Accepted Answer

Correct answer: B. From conditions we have, Moles of Fe=0.0056/56= 4 10mol 2 mol of Fe = 1 mol of alum 4 10mol of Fe =1/2× 4 10mol=0.5× 4 10mol

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