If NA is Avogadro’s number then number of valence electrons in 4.2 g of nitride ions (–) is — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
If NA is Avogadro’s number then number of valence electrons in 4.2 g of nitride ions ($N_3$–) is
💡 Solution & Explanation
Moles of 3 N ions= 4.2 0.3 14 Number of 3 N ions = 0.3 A N x But one 3 N ion contain 8 valence electrons ( . No . 7 2, 5. At N Valance electrons = 5 . For 3 N add 3 electrons which gives 8 valence electrons). 3 0.3 A N N x ions will contain 8 0.3 2.4 A A N N x x x of valence electrons. The correct option is (a) Note:- 1) For atom = No. of electron in outermost shell 2) For ions a) For anion = No. of electrons in outermost shell + No. of negative charge For cations = No. of electrons in outermost shell – No. of positive charge.