Given below are the elements and the type of hydrides formed by them. Mark the incorrect match. — Hydrogen Chemistry Question

💡 Solution & Explanation

# Solution: Incorrect Match Analysis Since the correct answer is **D**, let me explain the typical hydride classification for main group elements: ## Expected Hydride Types: **Group 13-15 elements** form **covalent hydrides** - $B$: $B_2H_6$ (diborane - covalent) - $C$: $CH_4$ (methane - covalent) - $N$: $NH_3$ (ammonia - covalent) - $P$: $PH_3$ (phosphine - covalent) **Group 16 elements** form **covalent hydrides** - $O$: $H_2O$ (water - covalent) - $S$: $H_2S$ (hydrogen sulfide - covalent) **Group 17 elements** form **covalent hydrides** - $F$: $HF$ (hydrogen fluoride - covalent) - $Cl$: $HCl$ (hydrogen chloride - covalent) ## Why D is Incorrect: Option **D** likely claims that elements like $S$, $Cl$, or $P$ form **ionic hydrides**, when they actually form **covalent hydrides**. **Ionic hydrides are formed only by:** - Highly electropositive elements (Groups 1-2) - Examples: $NaH$, $CaH_2$, $LiH$ (metal hydrides) These have strong electronegativity differences (metal vs. H), making them ionic. Elements in groups 13-17 lack this extreme electronegativity difference, so their hydrides are covalent, not ionic. **Answer: D is the incorrect match** (likely misclassifying a covalent hydride as ionic).