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The effective atomic number for the complex ion [Pd()6]4+ is — Coordination Compounds Chemistry Question

Question

The effective atomic number for the complex ion [Pd($NH_3$)6]4+ is

Answer: C

💡 Solution & Explanation

Electronic configuration of Pd in +4 oxidation state. [Kr]4d6 Atomic number of the complex = 42 (2 6) 54 x Hence, the correct answer is option (c)

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