0.052 100.052 6 / 60 x x x x b b b b b o b T T T T T T C 102. An aqueous solution of Glucose freezes at –0.186oC. Given that 0.512 H O b K K kg mol and 1.86 H O f K K kg mol , the elevation in boiling

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0.052 100.052 6 / 60 x x x x b b b b b o b T T T T T T C 102. An aqueous solution of Glucose freezes at –0.186oC. Given that 0.512 H O b K K kg mol and 1.86 H O f K K kg mol , the elevation in boiling point of this solution is

Prashant Kotian · Accepted Answer

Correct answer: B. f f T K m x b b T K m x 0.186 1.86 xm 0.1 / m mol kg 0.512 0.1 0.0512 x o bT C 103. On freezing an aqueous solution of sugar, the solid that starts separating out is (a) sugar (b) ice (c) solution with the same composition (d) solution with a different composition. Depression in Freezing point states that- f f T K m , where f T =depression in freezing SOLUTIONS 46 point, f K =molal freezing point constant and m=molality. The temperature at which liquid and the solid state exist in equilibrium and have same vapour pressure is called freezing point. When vapor pressure of

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