The solubility of in water is 2.33 × 10–3g L–1.Its solubility product will be (molecular weight of = — Ionic Equilibrium Chemistry Question
Question
The solubility of $BaSO_4$ in water is 2.33 × 10–3g L–1.Its solubility product will be (molecular weight of $BaSO_4$ = 223)
Answer: B
💡 Solution & Explanation
The solubility product can be found as- Concentration of barium and sulphate ions will be- Given weight/ molecular weight. IONIC EQUILIBRIUM 48 3 5 2.33 10 / 223 1.0 10 x x 2 2 4 4 2 2 sp 4 5 5 sp 10 sp BaSO Ba SO K [Ba ][SO ] K [1.0 10 ][1.0 10 ] K 1 10 x x x
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