What is the pH of a 0.015 M Ba(OH)2 solution ? — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

2 2 Ba OH Ba 2OH -> Thus, OH 0.015 2 0.03M x pOH = log OH 2 = log 3 10 x = 2 log3 1.52 And, pH + pOH = 14 pH = 14 – 1.52 = 12.48