What is the pH of a 0.015 M Ba(OH)2 solution ? | Ionic Equilibrium — Chem-Mantra | Chem-Mantra

⚗️ Chem-Mantra JEE Advanced Chemistry →

Ionic EquilibriummediumMCQ SINGLE

Question

What is the pH of a 0.015 M Ba(OH)2 solution ?

Answer: C

💡 Solution & Explanation

2 2 Ba OH Ba 2OH -> Thus, OH 0.015 2 0.03M x pOH = log OH 2 = log 3 10 x = 2 log3 1.52 And, pH + pOH = 14 pH = 14 – 1.52 = 12.48

💬

Still have doubts about this question?

Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes

Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

Explore Courses →Free on YouTube

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry