Ionic EquilibriummediumMCQ SINGLE

The pKb of CNis 4.7. The pH of solution prepared by mixing 2.5 mol of KCN of 2.5 mol of HCN in waterIonic Equilibrium Chemistry Question

Question

The pKb of CNis 4.7. The pH of solution prepared by mixing 2.5 mol of KCN of 2.5 mol of HCN in water and making the total volume up to 500 mL is

Answer: B

💡 Solution & Explanation

KCN and HCN make an acidic buffer solution. Molarity of 2.5 mole KCN 1000 5 Molar 500 x Molarity of 2.5 mole HCN 1000 5 Molar 500 x b pK of CN= 4.7 that means a pK of HCN = 9.3 salt pH pK log acid a pH 9.3 log1 9.3

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry