The correct representation for solubility product of is — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

# Solubility Product of $SnS_2$ **Step 1: Write the dissolution equation** $$SnS_2(s) \rightleftharpoons Sn^{4+}(aq) + 2S^{2-}(aq)$$ **Step 2: Identify the ions produced** When one mole of $SnS_2$ dissolves: - 1 mole of $Sn^{4+}$ is released - 2 moles of $S^{2-}$ are released **Step 3: Apply the $K_{sp}$ expression** The solubility product constant includes only dissolved ionic species (not the solid): $$K_{sp} = [Sn^{4+}][S^{2-}]^2$$ The exponent on $[S^{2-}]$ equals the stoichiometric coefficient (2) from the balanced equation. **Answer: A is $K_{sp} = [Sn^{4+}][S^{2-}]^2$** This correctly reflects that $Sn^{4+}$ appears once and $S^{2-}$ appears twice in the ionic product expression.