What is the value of Ksp for ? — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

The solubility product can be found as- 2 2 2 2 sp PbCl Pb 2Cl K [Pb ][Cl ] 124. The solubility of CaF2 is 2 × 10–4 mole/litre. Its solubility product is (a) 2.0 × 10–4 (b) 4.0 × 10–8 (c) 4 × 8.0 × 10–12 (d) 3.2 × 10–4. The solubility of calcium fluoride is given. Therefore, the solubility product can be found as- 2+ 2 2 2 sp 4 4 2 sp 12 sp CaF Ca 2F K [Ca ][2F ] K [2 10 ][4 10 ] K 4 8 10 x x xx