The solubility product of a sparingly soluble salt AB at room temperature is 1.21 Γ 10β6 M2. Its mol β Ionic Equilibrium Chemistry Question
Question
The solubility product of a sparingly soluble salt AB at room temperature is 1.21 Γ 10β6 M2. Its molar solubility is
Answer: C
π‘ Solution & Explanation
The solubility can be found as- Let concentration of A and B ions will be- x IONIC EQUILIBRIUM 47 sp 6 2 6 6 3 AB A B K [A ][B ] 1.21 10 [ ][ ] [ ] 1.21 10 [ ] 1.21 10 1.1 10 M x x x x x x x x
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