The volume of ammonia obtained by the combination of 10 mL of and 30 mL of is :

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Question

The volume of ammonia obtained by the combination of 10 mL of $N_2$ and 30 mL of $H_2$ is :

Prashant Kotian · Accepted Answer

Correct answer: A. 2 2 3 (10 ) 3 (30 ) 2 (20 ) N ml H ml NH ml -> It is given that Volume of 2 N ( 2 N V ) =10 ml Volume of 2 H ( 2 H V ) =30 ml The stoichiometric ratio can be shown as- 2 2 10 1 30 3 N H V V Now, 2 2 3 3 2 3 2 10 ml 30 ml 20 ml N H NH V V V -> 3 Volume of NH produced=20 ml

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