The free energy of formation of NO is 78 kJ mol–1 at the temperature of an automobile engine (1000 K). What is the equilibrium constant for this reaction at 100 | Chemical Equilibrium — Chem-Mantra | Chem-Mantra

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Question

The free energy of formation of NO is 78 kJ mol–1 at the temperature of an automobile engine (1000 K). What is the equilibrium constant for this reaction at 1000 K ? N (g) O (g) NO(g)

Answer: A

💡 Solution & Explanation

According to the equation, ° eq eq eq 5 eq ΔG 2.303RT log K 78000 log K 2.303 8.314 1000 log K 4.07 K =8.4 10 x x x

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