The equilibrium concentration of X, Y and YX2 are 4, 2 and 2 moles respectively for the equilibrium — Chemical Equilibrium Chemistry Question

💡 Solution & Explanation

# Solution: Finding Kc for the Equilibrium **Given Information:** - Equilibrium: $2X + Y \rightleftharpoons YX_2$ - $[X]_{eq} = 4$ mol/L - $[Y]_{eq} = 2$ mol/L - $[YX_2]_{eq} = 2$ mol/L **Step 1: Write the equilibrium constant expression** $$K_c = \frac{[YX_2]}{[X]^2[Y]}$$ Note: Coefficients in the balanced equation become exponents in the $K_c$ expression. **Step 2: Substitute equilibrium concentrations** $$K_c = \frac{(2)}{(4)^2(2)}$$ **Step 3: Calculate** $$K_c = \frac{2}{16 \times 2} = \frac{2}{32} = \frac{1}{16}$$ $$K_c = 0.0625 \text{ or } \frac{1}{16}$$ **Answer: B** — The value of $K_c = \frac{1}{16}$ or $0.0625$