Hydrocarbon (A) reacts with bromine by substitution to form an alkyl bromide which by Wurtz reaction — Haloalkanes and Haloarenes Chemistry Question

💡 Solution & Explanation

The final product of the Wurtz reaction is a gaseous alkane with fewer than four carbon atoms, which must be ethane ($C_2H_6$). Ethane is symmetrically formed by the coupling of methyl bromide ($CH_3Br$). Therefore, the original starting hydrocarbon (A) must be methane ($CH_4$).