Consider a perfectly homologous series of primary, straight-chain alkyl chlorides ranging from to : — Haloalkanes and Haloarenes Chemistry Question
Question
Consider a perfectly homologous series of primary, straight-chain alkyl chlorides ranging from $C_1$ to $C_6$: 1. $CH_3Cl$ 2. $C_2H_5Cl$ 3. $C_3H_7Cl$ 4. $C_4H_9Cl$ 5. $C_5H_{11}Cl$ 6. $C_6H_{13}Cl$ As the number of hydrophobic carbon atoms systematically increases, the phase behavior of these compounds fundamentally changes. Exactly how many of these specific listed compounds are considered freely miscible (soluble in all proportions) with pure liquid water at standard room temperature?
💡 Solution & Explanation
None of the alkyl halides—regardless of whether they possess a very short carbon chain like methyl chloride or a long chain like hexyl chloride—are freely miscible with water. Because they cannot act as hydrogen bond donors or effective hydrogen bond acceptors, they are utterly incapable of breaking the highly stable, pre-existing water-water hydrogen bonding network. Thus, they are all virtually insoluble in aqueous environments. Total count = 0.