In the context of free-radical halogenation, why are the hydrogen atoms attached directly to the aro β Haloalkanes and Haloarenes Chemistry Question
Question
In the context of free-radical halogenation, why are the hydrogen atoms attached directly to the aromatic ring in benzene or the double bond in ethylene considered practically completely inert compared to simple aliphatic alkanes?
π‘ Solution & Explanation
Vinylic and aryl $C-H$ bonds are extremely strong (BDE $\approx 110$ kcal/mol compared to $\approx 98$ kcal/mol for primary alkanes). This increased strength is due to the $sp^2$ hybridization of the carbon, which has greater s-character and holds the electrons closer to the nucleus. Furthermore, if a hydrogen were successfully abstracted, the resulting unpaired electron would reside in an $sp^2$ orbital that is situated in the plane of the molecule, perfectly orthogonal ($90^\circ$) to the adjacent pi-cloud. Therefore, it cannot participate in resonance delocalization, making the radical incredibly high in energy and practically impossible to form under mild conditions.