Two moles of an ideal gas () are compressed adiabatically and reversibly from 300 K to 500 K. What i — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

In an adiabatic process, heat exchange $q = 0$. By the First Law of Thermodynamics, $\Delta U = q + w$, which implies $w = \Delta U = nC_v(T_2 - T_1)$. Calculation: $w = 2 \text{ mol} \times 12.5 \text{ J K}^{-1}\text{mol}^{-1} \times (500 - 300) \text{ K} = 2 \times 12.5 \times 200 = 5000$ J.