What volume (in mL) of 0.1 M solution is required to completely oxidize 60 mL of 0.2 M solution in a — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Using the golden rule of titrations: $M_1 \times V_1 \times n_1 = M_2 \times V_2 \times n_2$. The n-factor for $K_2Cr_2O_7$ in an acidic medium is 6. The n-factor for $FeSO_4$ (where $Fe^{2+} \rightarrow Fe^{3+}$) is 1. Substituting the values: $0.1 \times V_1 \times 6 = 0.2 \times 60 \times 1 \Rightarrow 0.6 \times V_1 = 12 \Rightarrow V_1 = 20$ mL.