0.50 g of a solid mixture containing and requires exactly 30 mL of a 0.25 N solution for complete neutralization. What is the mass percentage of in the original mixture? (Atomic weights: K=39, Li=7)

Question

0.50 g of a solid mixture containing $K_2CO_3$ and $Li_2CO_3$ requires exactly 30 mL of a 0.25 N $HCl$ solution for complete neutralization. What is the mass percentage of $K_2CO_3$ in the original mixture? (Atomic weights: K=39, Li=7)

Prashant Kotian · Accepted Answer

Correct answer: 96. Let mass of (MW=138, E=69) be . Mass of (MW=74, E=37) is . Equivalents of acid used = eq. By Law of Equivalence: . Multiplying by gives: g. Mass percentage = .

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