3.0 g of a metal oxide is completely converted to 5.0 g of its corresponding metal chloride. Which o — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Let the equivalent weight of the metal be $E$. Equivalent weight of oxide = $E + 8$. Equivalent weight of chloride = $E + 35.5$. By the Law of Equivalence: $\frac{3}{E + 8} = \frac{5}{E + 35.5} \Rightarrow 3E + 106.5 = 5E + 40 \Rightarrow 2E = 66.5 \Rightarrow E = 33.25$. Equivalents = $3 / (33.25 + 8) = 3 / 41.25 = 0.0727$. Statements A, B, and D are correct.