One mole of an equimolar mixture of ferric oxalate, and ferrous oxalate, required moles of in an aci — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

1 mole of an equimolar mixture contains 0.5 moles of $Fe_2(C_2O_4)_3$ and 0.5 moles of $FeC_2O_4$. n-factor of $Fe_2(C_2O_4)_3$ is 6 ($Fe^{3+}$ doesn't oxidize, 3 oxalates $\times$ 2 = 6). n-factor of $FeC_2O_4$ is 3 (Fe=1, Oxalate=2). Total equivalents = $(0.5 \times 6) + (0.5 \times 3) = 3 + 1.5 = 4.5$ eq. For $KMnO_4$, Eq = $Moles \times 5 = 5x$. So $5x = 4.5 \Rightarrow x = 0.9$. Therefore, $10x = 9$.