Redox Reactions and Volumetric AnalysishardNUMERICAL

The equivalent weight of the complex salt when it acts as a reducing agent against is (where M is itRedox Reactions and Volumetric Analysis Chemistry Question

Question

The equivalent weight of the complex salt $K_2C_2O_4 \cdot 3H_2C_2O_4 \cdot 4H_2O$ when it acts as a reducing agent against $KMnO_4$ is $M/x$ (where M is its molar mass). What is the value of $x$?

Answer: 8

💡 Solution & Explanation

The salt contains one $C_2O_4^{2-}$ unit from potassium oxalate and three $C_2O_4^{2-}$ units from oxalic acid, giving a total of 4 moles of oxalate ions per mole of the complex. Each oxalate ion loses 2 electrons during oxidation to $CO_2$. Total electrons lost = $4 \times 2 = 8$. Therefore, the n-factor $x = 8$.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full NEET Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry