For the unbalanced disproportionation reaction in basic medium, which of the following statements ar — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Oxidation half: $P_4 + 8OH^- \rightarrow 4H_2PO_2^- + 4e^-$ ($\times 3$). Reduction half: $P_4 + 12H_2O + 12e^- \rightarrow 4PH_3 + 12OH^-$. Summing gives $4P_4 + 12OH^- + 12H_2O \rightarrow 4PH_3 + 12H_2PO_2^-$. Dividing by 4 gives $P_4 + 3OH^- + 3H_2O \rightarrow PH_3 + 3H_2PO_2^-$. All statements match.