The number of moles of required to completely react with one mole of ferrous oxalate () in an acidic — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

$FeC_2O_4$ oxidizes to $Fe^{3+}$ and $CO_2$. Fe goes from +2 to +3 (change = 1). $C_2O_4^{2-}$ goes from +3 to +4 (change = $1 \times 2 = 2$). Total n-factor = 1 + 2 = 3. $KMnO_4$ n-factor is 5. Equivalents must be equal: $n \times 5 = 1 \times 3 \Rightarrow n = 3/5$.