One mole of loses 10 moles of electrons to form a new compound Y. Assuming that all the nitrogen fro — Redox Reactions and Volumetric Analysis Chemistry Question
Question
One mole of $N_2H_4$ loses 10 moles of electrons to form a new compound Y. Assuming that all the nitrogen from $N_2H_4$ appears in the new compound and there is no change in the oxidation state of hydrogen, what is the oxidation state of nitrogen in compound Y?
Answer: 3
💡 Solution & Explanation
In $N_2H_4$, hydrogen is +1, so the initial O.S. of N is -2. Total charge contributed by the two N atoms = -4. When the molecule loses 10 electrons, the net charge on the nitrogen framework becomes $-4 - (-10) = +6$. Since there are 2 nitrogen atoms, the average O.S. of N in Y is $+6 / 2 = +3$.
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