An elementary chemical reaction has a total enthalpy change () of . If the activation energy for the — Reaction Mechanism Chemistry Question
Question
An elementary chemical reaction has a total enthalpy change ($\Delta H$) of $-45 \text{ kJ/mol}$. If the activation energy for the backward reaction ($E_b$) is experimentally determined to be $110 \text{ kJ/mol}$, what is the activation energy for the forward reaction ($E_f$) in $\text{kJ/mol}$?
Answer: 65
💡 Solution & Explanation
The relationship between enthalpy and activation energies is given by the formula $\Delta H = E_f - E_b$. Substituting the known values: $-45 = E_f - 110$. Solving for $E_f$ gives $E_f = 110 - 45 = 65 \text{ kJ/mol}$.
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