According to the Schoomaker and Stevenson rule, the bond length of a heteronuclear molecule is short — Periodic Table and Periodicity Chemistry Question
Question
According to the Schoomaker and Stevenson rule, the bond length $d_{A-B}$ of a heteronuclear molecule is shorter than the sum of their covalent radii due to ionic resonance. If $r_A = 0.80 \text{ \AA}$, $r_B = 1.10 \text{ \AA}$, and their Pauling electronegativities are $X_A = 3.5$ and $X_B = 1.5$, what is the predicted bond length $d_{A-B}$?
Answer: B
💡 Solution & Explanation
The Schoomaker & Stevenson equation is $d_{A-B} = r_A + r_B - 0.09 | X_A - X_B | $. Substituting the given values: $d_{A-B} = 0.80 + 1.10 - 0.09(3.5 - 1.5) = 1.90 - 0.09(2.0) = 1.90 - 0.18 = 1.72 \text{ \AA}$.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes