Consider the elements , and . Exactly how many of these elements have a standard Pauling electronega β Periodic Table and Periodicity Chemistry Question
Question
Consider the elements $C, N, O, F, P, S$, and $Cl$. Exactly how many of these elements have a standard Pauling electronegativity value that is GREATER THAN OR EQUAL TO $3.0$?
Answer: 4
π‘ Solution & Explanation
The standard Pauling values are approximately: C (2.5), N (3.0), O (3.5), F (4.0), P (2.1), S (2.5), Cl (3.0). The elements with values $\ge 3.0$ are Nitrogen, Oxygen, Fluorine, and Chlorine. Therefore, exactly 4 elements meet this condition.
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